25s=5s+10s^2

Solution for 25s=5s+10s^2 equation:

25s=5s+10s^2

We move all terms to the left:

25s-(5s+10s^2)=0

We get rid of parentheses

-10s^2-5s+25s=0

We add all the numbers together, and all the variables

-10s^2+20s=0

a = -10; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·(-10)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*-10}=\frac{-40}{-20}
=+2
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*-10}=\frac{0}{-20}
=0
$